25x^2-100x+51=0

Solution for 25x^2-100x+51=0 equation:

25x^2-100x+51=0

a = 25; b = -100; c = +51;
Δ = b2-4ac
Δ = -1002-4·25·51
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4900}=70$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-70}{2*25}=\frac{30}{50}
=3/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+70}{2*25}=\frac{170}{50}
=3+2/5
$